Ex 1.1, 4 - Chapter 1 Class 10 Real Numbers

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Ex 1.1, 4 Given that HCF (306, 657) = 9, find LCM (306, 657). We know that H.C.F × L.C.M = Product of numbers 9 × L.C.M = 306 × 657 L.C.M = (306 × 657)/9 L.C.M = 22338 ∴ L.C.M of 306 & 657 is 22338

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo