Example 5 (ii) - Chapter 4 Class 7 Simple Equations
Last updated at April 16, 2024 by Teachoo
Examples
Example 1 (ii) Important
Example 1 (iii) Important
Example 1 (iv)
Example 2 (i) Important
Example 2 (ii)
Example 2 (iii)
Example 2 (iv) Important
Example 3
Example 4 Important
Example 5 (i)
Example 5 (ii) Important You are here
Example 6
Example 7 (a)
Example 7 (b) Important
Example 8
Example 9 Important
Example 10 Important
Last updated at April 16, 2024 by Teachoo
Example 5 Solve: (b) 2p – 1 = 23 2p − 1 = 23 Adding 1 to both sides. 2p − 1 + 1 = 23 + 1 2p = 24 Dividing 2 both sides 2𝑝/2 = 24/2 p = 12