Ex 1.2
Ex 1.2, 2 (a) Important
Ex 1.2, 2 (b)
Ex 1.2, 3 (i)
Ex 1.2, 3 (ii) Important
Ex 1.2, 4
Question 1 5 (a)
Question 1 5 (b) Important
Question 1 5 (c)
Question 1 5 (d) Important
Question 1 5 (e) Important
Question 1 5 (f)
Question 1 5 (g) Important
Question 1 5 (h) You are here
Question 2
Question 3 Important
Question 4 Important
Question 5
Last updated at April 16, 2024 by Teachoo
Ex 1.2, 5 Find the product, using suitable properties: (h) (–57) × (–19) + 57 (−57) × (−19) + 57 = 57 × 19 + 57 Taking 57 common = 57 × (19 + 1) = 57 × 20 = 57 × 2 × 10 = 114 × 10 = 1140