Question 4 (ii) - Examples - Chapter 8 Class 8 Algebraic Expressions and Identities

Last updated at Dec. 16, 2024 by

Example 14 - Chapter 9 Class 8 Algebraic Expressions and Identities - Part 2

Example 14 - Chapter 9 Class 8 Algebraic Expressions and Identities - Part 3

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Example 14 Use the Identity (π‘₯+π‘Ž)(π‘₯+𝑏)=π‘₯^2+(π‘Ž+𝑏)π‘₯+π‘Žπ‘ to find the following: (ii) 95 Γ— 103 95 Γ— 103 = (100βˆ’5)Γ—(100+3) = [100+(βˆ’5)]Γ—[100+3] (π‘₯+π‘Ž)(π‘₯+𝑏)=π‘₯^2+(π‘Ž+𝑏)π‘₯+π‘Žπ‘ Putting π‘₯ = 100 , π‘Ž = βˆ’5 & 𝑏 = 3 = (100)^2+(βˆ’5+2)(100)+(βˆ’5)(3) = 10000+(βˆ’2Γ—100)+(βˆ’15) = 10000βˆ’200βˆ’15 = 1000βˆ’215 = πŸ—πŸ•πŸ–πŸ“

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo