Slide26.JPG

Slide27.JPG
Slide28.JPG

Go Ad-free

Transcript

Ex13.2, 7 For some constants a and b, find the derivative of (iii) (x − a)﷮(x − b)﷯ Let f(x) = (x − a)﷮(x − b)﷯ Let u = (x – a) & v = (x – b) So, f(x) = 𝑢﷮𝑣﷯ f’(x) = 𝑢﷮𝑣﷯﷯﷮′﷯ f’(x) = 𝑢﷮′﷯𝑣 − 𝑣﷮′﷯𝑢﷮ 𝑣﷮2﷯﷯ Finding u’ & v’ u = x – a u’ = 1. x1–1 – 0 = x0 = 1 v = x – b v’ = 1.x1–1 – b = 1.x0 = 1 f’(x) = 𝑢﷮𝑣﷯﷯﷮′﷯ = 𝑢﷮′﷯𝑣 − 𝑣﷮′﷯𝑢﷮ 𝑣﷮2﷯﷯ = 1 x − b﷯ − (1) x − a﷯ ﷮ x − b﷯2﷯ = 1 x − b﷯ − (1) x − a﷯ ﷮ x − b﷯2﷯ = x − b − x + a﷮ x − b﷯2﷯ = − b + a﷮ x − b﷯2﷯ = a − b﷮ x − b﷯2﷯ Hence, f’ (x) = 𝐚 − 𝐛﷮ 𝐱 − 𝐛﷯𝟐﷯

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo