
Examples
Last updated at Dec. 16, 2024 by Teachoo
Transcript
Example 2 Find the limits: (iv) limβ¬(xβ2) [(x3 β2π₯2)/(x2β5x+6)] limβ¬(xβ2) [(x3 β 2π₯2)/(x2 β 5x + 6)] = limβ¬(xβ2) ((x2 (x β 2))/(π₯2 β 3π₯ β 2π₯ + 6)) = limβ¬(xβ2) ((x2 (x β 2))/(x (x β 3) β 2 (x β 3) )) = limβ¬(xβ2) ((x2 (x β 2))/((x β 2) (x β 3) )) = (π₯π’π¦)β¬(π±βπ) ((π±π )/((π± β π) )) Putting x = 2 = (2)2/(2 β 3) = (2)2/(2 β 3) = 4/(β1) = β 4