Misc 1 (ii) - Chapter 8 Class 12 Application of Integrals

Last updated at Dec. 16, 2024 by

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Misc 1 Find the area under the given curves and given lines: (ii) 𝑦= 𝑥4, 𝑥 = 1, 𝑥 = 5 and 𝑥-axisArea required = Area ABCD = ∫_1^5▒〖𝑦 𝑑𝑥〗 y → Equation of curve 𝑦=𝑥^2 Thus, Area required = ∫_1^5▒〖𝑦 𝑑𝑥〗 =∫_𝟏^𝟓▒〖𝒙^𝟒 𝒅𝒙〗 =[𝑥^5/5]_1^5 =5^5/5−1^5/5 =5^4−1/5 = 625 – 0.2 = 624.8 square units

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo