Example 8 (ii) - Chapter 7 Class 12 Integrals

Last updated at April 16, 2024 by Teachoo

Example 8 - Chapter 7 Class 12 Integrals - Part 2

Example 8 - Chapter 7 Class 12 Integrals - Part 3

Next: Example 9 (i) → Go Ad-free

Transcript

Example 8 Find the following integrals: (ii) ∫1▒𝑑𝑥/√(2𝑥 − 𝑥^2 ) ∫1▒𝑑𝑥/√(2𝑥 − 𝑥^2 ) Adding and subtracting 1 in denominator = ∫1▒𝑑𝑥/√(−〖 𝑥〗^2 + 2𝑥 + 1−1) = ∫1▒𝑑𝑥/√(1 − 𝑥^2 + 2𝑥 − 1) = ∫1▒𝑑𝑥/√(1 − (𝑥^2 − 2𝑥 + 1) ) = ∫1▒𝑑𝑥/√(1 −〖 (𝑥 − 1)〗^2 ) = ∫1▒𝑑𝑥/√(1^2 −〖 (𝑥 − 1)〗^2 ) =sin^(−1)⁡〖(𝑥 − 1)/1+C〗 =〖𝒔𝒊𝒏〗^(−𝟏)⁡〖(𝒙−𝟏)+𝑪〗 It is of the form 𝑑𝑥/√(𝑎^2 − 𝑥^2 )=sin^(−1) 𝑥/𝑎+𝐶 Replacing a with 1 and 𝑥 with 𝑥−1

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo

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