Question 17 - NCERT Exemplar - MCQ - Chapter 8 Class 10 Introduction to Trignometry

Last updated at Dec. 16, 2024 by

sin (45° + θ) – cos (45° – θ) is equal to

(A) 2 cos θ  

(B) 0 

(C) 2 sin θ  

(D) 1

Slide28.JPG

Go Ad-free

Transcript

Question 17 sin (45° + θ) – cos (45° – θ) is equal to (A) 2 cos θ (B) 0 (C) 2 sin θ (D) 1 Now, sin (45° + θ) – cos (45° – θ) Using sin A = cos (90° − A) = cos (90° − [45° + θ] ) – cos (45° – θ) = cos (90° − 45° − θ) – cos (45° – θ) = cos (45° − θ) – cos (45° – θ) = 0 So, the correct answer is (B)

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo