Question 6 - Past Year MCQ - Chapter 14 Class 10 Probability

Last updated at Dec. 16, 2024 by

Question 6

Two different coins are tossed simultaneously. The  probability of getting at least one head is:

(a) 1/4                                                               (b) 1/8

(c) 3/4                                                               (d) 7/8

Two different coins are tossed simultaneously - MCQ Probability Class - Past Year MCQ

part 2 - Question 6 - Past Year MCQ - Serial order wise - Chapter 14 Class 10 Probability

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Transcript

Question 6 Two different coins are tossed simultaneously. The probability of getting at least one head is: (a) 1/4 (b) 1/8 (c) 3/4 (d) 7/8 When 2 coins are tossed Possible outcomes = HH, TH, HT, TT Now, Outcomes with atleast with 1 head = HH, HT, TH Thus, P(getting atleast 1 head) = (๐‘๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘œ๐‘ข๐‘ก๐‘๐‘œ๐‘š๐‘’๐‘  ๐‘ค๐‘–๐‘กโ„Ž ๐‘Ž๐‘ก๐‘™๐‘’๐‘Ž๐‘ ๐‘ก 1 โ„Ž๐‘’๐‘Ž๐‘‘)/(๐‘‡๐‘œ๐‘ก๐‘Ž๐‘™ ๐‘›๐‘ข๐‘š๐‘๐‘’๐‘Ÿ ๐‘œ๐‘“ ๐‘œ๐‘ข๐‘ก๐‘๐‘œ๐‘š๐‘’๐‘ ) = ๐Ÿ‘/๐Ÿ’ So, the correct answer is (C)

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