Ex 11.1, 3 - Chapter 13 Class 9 Surface Areas and Volumes (Important Question)
Last updated at April 16, 2024 by Teachoo
Chapter 13 Class 9 Surface Areas and Volumes
Question 2
Important
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Class 9
Important Questions for Exam - Class 9
- Chapter 1 Class 9 Number Systems
- Chapter 2 Class 9 Polynomials
- Chapter 3 Class 9 Coordinate Geometry
- Chapter 4 Class 9 Linear Equations in Two Variables
- Chapter 5 Class 9 Introduction to Euclid's Geometry
- Chapter 6 Class 9 Lines and Angles
- Chapter 7 Class 9 Triangles
- Chapter 8 Class 9 Quadrilaterals
- Chapter 9 Class 9 Areas of parallelograms and Triangles
- Chapter 10 Class 9 Circles
- Chapter 11 Class 9 Constructions
- Chapter 12 Class 9 Herons Formula
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Chapter 13 Class 9 Surface Areas and Volumes
- Chapter 14 Class 9 Statistics
- Chapter 15 Class 9 Probability
Transcript
Ex 11.1, 3 Curved surface area of a cone is 308 cm2 and its slant height is 14 cm. Find radius of the base and [ =22/7] It is given that Curved Surface Area of cone =308 rl = 308 22/7 14= 308 22 2= 308 r = (308/(2 22)) cm r = 7 cm Therefore, the radius of the circular end of the cone is 7 cm. Ex 11.1, 3 Curved surface area of a cone is 308 cm2 and its slant height is 14 cm. Find (ii) total surface area of the cone. [ =22/7] We know that l = 14 cm, r = 7 cm Total surface area of cone = r(l + r) = 22/7 7 (14 + 7) = 22/7 7 21 = 22 1 21 = 462 cm2 Therefore, the total surface area of the cone is 462 cm2.
