Question 3 - Case Based Questions (MCQ) - Chapter 7 Class 10 Coordinate Geometry
Last updated at Dec. 16, 2024 by Teachoo
Ayush Starts walking from his house to office. Instead of going to the office directly, he goes to a bank first, from there to his daughter's school and then reaches the office. (Assume that all distances covered are in straight lines). If the house is situated at (2, 4), bank at (5, 8), school at (13, 14) and office at (13, 26) and coordinates are in km.
Question 1
What is the distance between house and bank?
(a) 5 km
(b) 10 km
(c) 12 km
(d) 27 km
Question 2
What is the distance between Daughter's School and bank?
(a) 5 km
(b) 10 km
(c) 12 km
(d) 27 km
Question 3
What is the distance between house and office?
(a) 24.6 km
(b) 26.4 km
(c) 24 km
(d) 26 km
Question 4
What is the total distance travelled by Ayush to reach the office?
Question Ayush Starts walking from his house to office. Instead of going to the office directly, he goes to a bank first, from there to his daughter's school and then reaches the office. (Assume that all distances covered are in straight lines). If the house is situated at (2, 4), bank at (5, 8), school at (13, 14) and office at (13, 26) and coordinates are in km.
Question 1 What is the distance between house and bank? (a) 5 km (b) 10 km (c) 12 km (d) 27 km
Given that
House (2, 4)
& Bank (5, 8)
Now,
Distance b/w house and bank = β((π₯_2βπ₯_1 )^2+(π¦_2βπ¦_1 )^2 )
= β((πβπ)^π+(πβπ)^π )
= β((3)^2+(4)^2 )
= β(9+16)
= β25
= β(5^2 )
= 5 km
So, the correct answer is (B)
Question 2 What is the distance between Daughter's School and bank? (a) 5 km (b) 10 km (c) 12 km (d) 27 km
Given that
School (13, 14)
& Bank (5, 8)
Now,
Distance b/w school and bank = β((π₯_2βπ₯_1 )^2+(π¦_2βπ¦_1 )^2 )
= β((πβππ)^π+(πβππ)^π )
= β((β8)^2+(β6)^2 )
= β(64+36)
= β100
= β(10^2 )
= 10 km
So, the correct answer is (B)
Question 3 What is the distance between house and office? (a) 24.6 km (b) 26.4 km (c) 24 km (d) 26 km
Given that
House (2, 4)
& Office (13, 26)
Now,
Distance b/w house and office = β((π₯_2βπ₯_1 )^2+(π¦_2βπ¦_1 )^2 )
= β((ππβπ)^π+(ππβπ)^π )
= β((11)^2+(22)^2 )
= β((11)^2+(2 Γ 11)^2 )
= β((11)^2+2^2 (11)^2 )
= β((11)^2 (1+2^2 ) )
= β((11)^2 (1+4) )
= β((11)^2 Γ 5)
= ππβπ
= 11 Γ 2.23
= 24.53 km
~ 24.6 km
So, the correct answer is (A)
Question 4 What is the total distance travelled by Ayush to reach the office? (a) 5 km (b) 10 km (c) 12 km (d) 27 km
Now, our diagram looks like
Letβs find Distance from School to Office
Given that
House (13, 14) & Office (13, 26)
Now,
Distance b/w school and office = β((π₯_2βπ₯_1 )^2+(π¦_2βπ¦_1 )^2 )
= β((ππβππ)^π+(ππβππ)^π )
= β(0^2+(12)^2 )
= β(12^2 )
= 12 km
Thus, our diagram looks like
Total distance travelled
= House to Bank + Bank to School + School to Office
= 5 + 10 + 12
= 27 km
So, the correct answer is (D)
Question 5 What is the extra distance travelled by Ayush? (a) 2 km (b) 2.2 km (c) 2.4 km (d) none of these
Extra distance travelled by Ayush
= Distance travelled β Distance from House to Office
= 27 β 24.6
= 2.4 km
So, the correct answer is (C)
Made by
Davneet Singh
Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo
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