Chapter 13 Class 9 Surface Areas and Volumes
Question 6 Important
Question 7 Important
Question 3 Important
Question 4 Important You are here
Question 9 Important
Example 3 Important
Ex 11.1, 3 Important
Ex 11.1, 5 Important
Ex 11.2, 3 Important
Ex 11.2, 8 Important
Ex 11.2, 9 Important
Question 6 Important
Question 8 Important
Question 9 Important
Question 7 Important
Question 3 Important
Question 7 Important
Ex 11.3, 5 Important
Ex 11.3, 6 Important
Ex 11.3, 7 Important
Ex 11.3, 8 Important
Example 11 Important
Ex 11.4, 4 Important
Surface Area and Volume Formulas Important
Chapter 13 Class 9 Surface Areas and Volumes
Last updated at Dec. 13, 2024 by Teachoo
Question 4 The diameter of a roller is 84 cm and its length is 120 cm. It takes 500 complete revolutions to move once over to level a playground. Find the area of the playground in m2? [𝐴𝑠𝑠𝑢𝑚𝑒 𝜋= 22/7] Roller is of form cylinder Radius = 𝐷𝑖𝑎𝑚𝑒𝑡𝑒𝑟/2 = 84/2 = 42 cm Area of roller = Curved surface of cylinder = 2πrh = (2×22/7×42×120) cm2 = 31680 cm2 Area of 1 revolution = Area of roller = 31680 cm2 Area of 500 revolution = 500 × 31680 cm2 Area of playground = 15840000 cm2 = 15840000 ×1/(100 ) ×1/(100 )m2 = 1584 m2