Question John and Jivanti are playing with the marbles in the playground. They together have 45 marbles and John has 15 marbles more than Jivanti.
Question 1 The number of marbles Jivanti had: (a) 15 (b) 30 (c) 40 (d) 5
Let Number of marbles with John = x
Number of marbles with Jivanti = y
Given that
They together have 45 marbles
x + y = 45
And, John has 15 marbles more than Jivanti
x = y + 15
x – y = 15
Adding (1) and (2)
(x + y) + (x − y) = 45 + 15
2x = 60
x = 60/2
x = 30
Putting x = 30 in (1)
x + y = 45
30 + y = 45
y = 45 − 30
y = 15
So, x = 30 and y = 15
Thus,
Number of marbles with John = x = 30
Number of marbles with Jivanti = y = 15
So, the correct answer is (A)
Question 2 The number of marbles John had: (a) 40 (b) 30 (c) 15 (d) 20
Number of marbles with John = 30
So, the correct answer is (B)
Question 3 If 45 is replaced by 55 in the above case discussed in the question, then the number of marbles Jivanti have: (a) 15 (b) 30 (c) 20 (d) 35
If 45 is replaced by 55, our equations will be
x + y = 55 ...(1)
x – y = 15 ...(2)
Adding (1) and (2)
(x + y) + (x − y) = 55 + 15
2x = 70
x = 70/2
x = 35
Putting x = 35 in (1)
x + y = 55
35 + y = 55
y = 55 − 35
y = 20
Thus,
Number of marbles with John = x = 35
Number of marbles with Jivanti = y = 20
So, the correct answer is (C)
Question 4 According to the question 3, the number of marbles John have: (a) 30 (b) 40 (c) 45 (d) 35
From above question 3,
Number of marbles with John = x = 35
So, the correct answer is (D)
Question 5 The given problem is based on which mathematical concept? (a) pair of linear equations (b) Quadratic equations (c) Polynomials (d) None of the above
The given Problem is based on Pair of linear equations.
So, the correct answer is (A)
Made by
Davneet Singh
Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo
Hi, it looks like you're using AdBlock :(
Displaying ads are our only source of revenue. To help Teachoo create more content, and view the ad-free version of Teachooo... please purchase Teachoo Black subscription.
Please login to view more pages. It's free :)
Teachoo gives you a better experience when you're logged in. Please login :)
Solve all your doubts with Teachoo Black!
Teachoo answers all your questions if you are a Black user!