Chapter 12 Class 12 Linear Programming
Serial order wise

A dealer in rural area wishes to purchase a number of sewing machines. He has only Rs. 5,760 to invest and has space for at most 20 items for storage. An  electronic sewing machine cost him Rs. 360 and a  manually operated sewing machine Rs. 240. He can  sell an electronic sewing machine at a profit of Rs. 22 and a manually operated machine at a profit of Rs. 18. Assume that the electronic sewing machines  he can sell is x and that of manually operated  machines is y.

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Question 1

The objective function is  _______.

(a) Maximise Z = 360x + 240y

(b) Maximise Z = 22x + 18y

(c) Minimise Z = 360x + 240y

(d) Minimise Z = 22x + 18y

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Question 2

The maximum value of x + y is  _______.

(a) 5760 

(b) 18

(c) 22    

(d) 20

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Question 3

Which of the following is not a constraint?

(a) x + y ≥ 20   

(b) 360x + 240y ≤ 5760

(c) x ≥ 0   

(d) y ≥ 0

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Question 4

The profit is maximum when (x, y) =  _______.

(a) (5, 15) 

(b) (8, 12)

(c) (12, 8)  

(d) (15, 5)

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Question 5

The maximum profit is Rs.  _______.

(a) 5760 

(b) 392

(c) 362 

(d) 290
 

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Transcript

Question A dealer in rural area wishes to purchase a number of sewing machines. He has only Rs. 5,760 to invest and has space for at most 20 items for storage. An electronic sewing machine cost him Rs. 360 and a manually operated sewing machine Rs. 240. He can sell an electronic sewing machine at a profit of Rs. 22 and a manually operated machine at a profit of Rs. 18. Assume that the electronic sewing machines he can sell is x and that of manually operated machines is y. Let the Number of Electronic Sewing Machines = x Number of Manual Sewing Machines = y Given that He has space for at most 20 items for storage ∴ x + y ≤ 20 Also, An electronic sewing machine cost him Rs. 360 and a manually operated sewing machine Rs. 240. And, he has only Rs. 5,760 to invest ∴ Cost of electronic + Cost of manual ≤ 5760 Number of Electronic × 360 + Number of Manual × 240 ≤ 5760 360x + 240y ≤ 5760 Dividing both sides by 120 3x + 2y ≤ 48 Also, x ≥ 0, y ≥ 0 We would need to Maximize Profit He can sell an electronic sewing machine at a profit of Rs. 22 and a manually operated machine at a profit of Rs. 18 Z = 22x + 18y Combining all constraints : Maximize Z = 22x + 18y Subject to Constraints : x + y ≤ 20 3x + 2y ≤ 48 x ≥ 0, y ≥ 0 Question 1 The objective function is _______. (a) Maximise Z = 360x + 240y (b) Maximise Z = 22x + 18y (c) Minimise Z = 360x + 240y (d) Minimise Z = 22x + 18y Objective function is Maximize Z = 22x + 18y So, the correct answer is (B) Question 2 The maximum value of x + y is _______. (a) 5760 (b) 18 (c) 22 (d) 20 Since x + y ≤ 20 Thus, Maximum value of x + y is 20 So, the correct answer is (D) Question 3 Which of the following is not a constraint? (a) x + y ≥ 20 (b) 360x + 240y ≤ 5760 (c) x ≥ 0 (d) y ≥ 0 Our LPP is Maximize Z = 22x + 18y Subject to Constraints : x + y ≤ 20 3x + 2y ≤ 48 x ≥ 0, y ≥ 0 Since x + y ≤ 20, not greater than So, the correct answer is (A) Question 4 The profit is maximum when (x, y) = _______. (a) (5, 15) (b) (8, 12) (c) (12, 8) (d) (15, 5) Our LPP is Maximize Z = 22x + 18y Subject to Constraints : x + y ≤ 20 3x + 2y ≤ 48 x ≥ 0, y ≥ 0 So, the correct answer is (B) Question 4 The profit is maximum when (x, y) = _______. (a) (5, 15) (b) (8, 12) (c) (12, 8) (d) (15, 5) Our LPP is Maximize Z = 22x + 18y Subject to Constraints : x + y ≤ 20 3x + 2y ≤ 48 x ≥ 0, y ≥ 0 ∴ Z = 392 is maximum at (8, 12) So, the correct answer is (b) Question 5 The maximum profit is Rs. _______. (a) 5760 (b) 392 (c) 362 (d) 290 Since Z = 392 is maximum at (8, 12) ∴ Maximum Profit = Rs 392 So, the correct answer is (B)

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo