Question 1 - Case Based Questions (MCQ) - Chapter 5 Class 12 Continuity and Differentiability
Last updated at April 16, 2024 by Teachoo
Ms. Remka of city school is teaching chain rule to her students with the help of a flow-chart The chain rule says that if h and g are functions and
f
(
x
) =
g(h(x
)), then
Based on the above information, answer any four of the following questions.
Let f(x) = sin x and g(x) = x3
Question Ms. Remka of city school is teaching chain rule to her students with the help of a flow-chart The chain rule says that if h and g are functions and f(x) = g(h(x)), then Based on the above information, answer any four of the following questions. Let f(x) = sin x and g(x) = x3
Question 1 fog (x) = _______. (a) sin x3 (b) sin3 x (c) sin 3x (d) 3 sin x
Since f(x) = sin x and g(x) = x3
fog (x) = f(g(x))
= f (x3)
= sin (x3)
So, the correct answer is (A)
Question 2 gof (x) = _______. (a) sin x3 (b) sin3 x (c) sin 3x (d) 3 sin x
Since f(x) = sin x and g(x) = x3
gof (x) = g(f(x))
= g(sin x)
= (sin x)3
= sin3 x
So, the correct answer is (B)
Question 3 𝒅/𝒅𝒙 (sin3 x) = _______. (a) cos3 x (b) 3 sinx cos x (c) 3 sin2x cos x (d) −cos3 x
(sin3 x)’ = 3 sin2 x (sin x)’
= 3 sin2 x cos x
So, the correct answer is (C)
Question 4 𝒅/𝒅𝒙 (sin x3) _______. (a) cos (x)3 (b) −cos (x)3 (c) 3x2 sin (x)3 (d) 3x2 cos (x3)
[sin (x3)]’ = cos (x3) × (x3)’
= cos (x3) × 3x2
= 3x2 cos (x3)
So, the correct answer is (D)
Question 5 𝒅/𝒅𝒙 (sin 2x) at x = 𝜋/2 is _______. (a) 0 (b) 1 (c) 2 (d) −2
𝒅/𝒅𝒙 (sin 2x) = 2 cos 2x
Putting x = 𝜋/2
= 2 cos (2 × 𝜋/2)
= 2 cos 𝜋
= 2 × −1
= −2
So, the correct answer is (D)
Made by
Davneet Singh
Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo
Hi, it looks like you're using AdBlock :(
Displaying ads are our only source of revenue. To help Teachoo create more content, and view the ad-free version of Teachooo... please purchase Teachoo Black subscription.
Please login to view more pages. It's free :)
Teachoo gives you a better experience when you're logged in. Please login :)
Solve all your doubts with Teachoo Black!
Teachoo answers all your questions if you are a Black user!