Ex 3.7, 7 (Optional) - Chapter 3 Class 10 Pair of Linear Equations in Two Variables - Part 10

Ex 3.7, 7 (Optional) - Chapter 3 Class 10 Pair of Linear Equations in Two Variables - Part 11
Ex 3.7, 7 (Optional) - Chapter 3 Class 10 Pair of Linear Equations in Two Variables - Part 12
Ex 3.7, 7 (Optional) - Chapter 3 Class 10 Pair of Linear Equations in Two Variables - Part 13

 

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Question 7 Solve the following pair of linear equations: (iii) 𝑥/𝑎 – 𝑦/𝑏 = 0 ax + by = a2 + b2 𝑥/𝑎 − 𝑦/𝑏 = 0 …(1) ax + by = 𝑎2+𝑏2 …(2) Solving Equation (1) 𝑥/𝑎 − 𝑦/𝑏 = 0 (𝑏𝑥 − 𝑎𝑦)/𝑎𝑏 = 0 bx − ay = 0 Now, solving equations (2) & (3) bx − ay = 0 Multiplying both sides by b b(bx – ay) = b × 0 b2x − aby = 0 ax + by = a2 + b2 Multiplying both sides by a a(ax + by) = a(a2 + b2) a2x + aby = a3 + ab2 Hence, our equations are b2x − aby = 0 …(4) a2x + aby = a3 + ab2 …(5) From equation (4) b2x − aby = 0 b2x = aby aby = b2x y = (𝑏^2 𝑥)/𝑎𝑏 y = 𝑏𝑥/𝑎 Putting y = 𝑏𝑥/𝑎 in equation (5) a2x + aby = a3 + ab2 a2𝑥 + ab(𝑏𝑥/𝑎) = a3 + ab2 a2𝑥 + b2𝑥 = a3 + ab2 (a2 + b2) 𝑥 = a (a2 + b2) 𝑥 = (𝑎(𝑎^2 + 𝑏^2))/((𝑎^2 + 𝑏^2)) 𝒙 = a Putting 𝑥 = a in equation (4) b2𝑥 − aby = 0 b2(a) − aby = 0 ab2 − aby = 0 ab2 = aby aby = ab2 y = (𝑎𝑏^2)/𝑎𝑏 y = b Therefore, 𝒙 = a and y = b

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo