The pair of equations x + 2y + 5 = 0 and –3x – 6y  + 1 = 0 have: 

(a) a unique solution                       (b) exactly two solutions 

(c) infinitely many solutions            (d) no solution 

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Question 4 The pair of equations x + 2y + 5 = 0 and –3x – 6y + 1 = 0 have: (a) a unique solution (b) exactly two solutions (c) infinitely many solutions (d) no solution x + 2y + 5 = 0 Comparing with a1x + b1y + c1 = 0 ∴ a1 = 1 , b1 = 2 , c1 = 5 −3x − 6y + 1 = 0 Comparing with a2x + b2y + c2 = 0 ∴ a2 = −3 , b2 = −6 , c2 = 1 ∴ a1 = 1 , b1 = 2 , c1 = 5 & a2 = −3 , b2 = −6 , c2 = 1 Since 𝑎1/𝑎2 = 𝑏1/𝑏2 ≠ 𝑐1/𝑐2 So, we have no solution So, the correct answer is (D) 𝑎1/𝑎2 = 1/(−3) 𝑎1/𝑎2 = (−1)/3 𝑏1/𝑏2 = 2/(−6) 𝑏1/𝑏2 = (−1)/3 𝑐1/𝑐2 = 5/1

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo