Given that one of the zeroes of the cubic polynomial ax 3 + bx 2 + cx + d is zero, the product of the other two zeroes is:
(A) − c/a (b) c/a
(c) 0 (d) -b/a
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Last updated at Dec. 16, 2024 by Teachoo
Question 7 Given that one of the zeroes of the cubic polynomial ax3 + bx2 + cx + d is zero, the product of the other two zeroes is: (A) β c/a (b) c/a (c) 0 (d) βπ/a Let p(x) = ax3 + bx2 + cx + d Given that one zero is 0 β΄ πΆ = 0, and we need to find product of other other two zeroes, i.e. π·πΈ We know that Sum of product of Zeroes = π/π πΆπ· + π·πΈ + πΆπΈ = π/π 0 Γ π½ + π½πΎ + 0 Γ πΎ = π/π π·πΈ = π/π So, the correct answer is (B)