If one of the zeroes of the quadratic polynomial (k – 1) x 2

 + k x + 1 is –3, then the value of k is

(a) 4/3       (b) (-4)/3  (c) 2/3    (d) (-2)/3

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Question 3 If one of the zeroes of the quadratic polynomial (k – 1) x2 + kx + 1 is –3, then the value of k is (a) 4/3 (b) (−4)/3 (c) 2/3 (d) (−2)/3 Let p(x) = (k – 1) x2 + kx + 1 Since one zero is −3 Therefore, p(−3) = 0 (k – 1) (−3)2 + k(−3) + 1 = 0 9(k − 1) − 3k + 1 = 0 9k − 9 − 3k + 1 = 0 6k − 8 = 0 6k = 8 k = 8/6 k = 𝟒/𝟑 So, the correct answer is (A) 6k = 8 k = 8/6 k = 𝟒/𝟑 So, the correct answer is (A) 6k = 8 k = 8/6 k = 𝟒/𝟑 So, the correct answer is (A)

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo