Question P(x) = ćā5š„ć^2+125š„+37500 is the total profit function of a company, where x is the production of the company.
Question 1 What will be the production when the profit is maximum? (a) 37500 (b) 12.5 (c) ā12.5 (d) ā37500
Given
P(x) = ā5x2 + 125x + 37500
Differentiating w.r.t x
Pā(x) = d(ćā5š„ć^2 + 125š„ + 37500)/šš„
Pā(x) = ā5 Ć 2x + 125
Pā(x) = ā10x + 125
Putting Pā(x) = 0
ā10x + 125 = 0
ā10x = --125
x = (ā125)/(ā10)
x = 12.5
Finding Pāā(x)
Pāā(x) = d(ā10š„ + 125)/šš„
Pāā(x) = ā10
< 0
Since Pāā(š) < 0 at š„ = 12.5
ā“ š„ = 12.5 is point of maxima
Thus, P(š„) is maximum when š = 12.5
So, the correct answer is (b)
Question 2 What will be the maximum profit? (a) Rs 38,28,125 (b) Rs 38281.25 (c) Rs 39,000 (d) None
Putting x = 12.5 in P(x)
P(x) = ā5x2 + 125x + 37500
= ā5(12.5)2 + 125(12.5) + 37500
= ā5(156.25) + 1562.5 + 37500
= ā781.25 + 1562.5 + 37500
= 781.25 + 37500
= Rs 38281.25
So, the correct answer is (b)
Question 3 Check in which interval the profit is strictly increasing . (a) (12.5, ā) (b) for all real numbers (c) for all positive real numbers (d) (0, 12.5)
Profit is strictly increasing where
Pā(x) > 0
ā10x + 125 > 0
125 > 10x
10x < 125
x < 12.5
So, profit is strictly increasing for x ā (0, 12.5)
So, the correct answer is (d)
Question 4 When the production is 2 units, what will be the profit of the company? (a) 37,500 (b) 37,730 (c) 37,770 (d) None
Putting x = 2 in P(x)
P(x) = ā5x2 + 125x + 37500
= ā5(2)2 + 125(2) + 37500
= ā5(4) + 250 + 37500
= ā20 + 250 + 37500
= 230 + 37500
= Rs 37730
So, the correct answer is (b)
Question 5 What will be production of the company when the profit is Rs 38,250? (a) 15 (b) 30 (c) 2 (d) data is not sufficient to find
Putting P(x) = 38250 in formula of P(x)
P(x) = ā5x2 + 125x + 37500
38250 = ā5x2 + 125x + 37500
5x2 ā 125x ā 37500 + 38250 = 0
5x2 ā 125x + 750 = 0
Dividing both sides by 5
x2 ā 25x + 150 = 0
x2 ā 10x ā 15x + 150 = 0
x(x ā 10) ā 15(x ā 10) = 0
(x ā 10) (x ā 15) = 0
ā“ x = 10, 15
Since x = 15 is in the options
So, the correct answer is (a)
Made by
Davneet Singh
Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo
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