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Chapter 14 Class 10 Probability
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Question 2 - Case Based Questions (MCQ) - Chapter 14 Class 10 Probability

Last updated at April 16, 2024 by

This question is inspired from Example 13 - Chapter 15 Class 10 - Probability

Rahul and Ravi planned to play Business ( board game) in which they were supposed to use two dice

Rahul and Ravi planned to play Business - Teachoo.jpg

 

 

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Question 1

Ravi got first chance to roll the dice. What is the probability that he got the sum of the two numbers appearing on the top face of the dice is 8?

(a) 1/26                 (b) 5/36                 (c) 1/18                     (d) 0

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Question 2

Rahul got next chance. What is the probability that he got the sum of the two numbers appearing on the top face of the dice is 13?

(a) 1                     (b) 5/36                    (c) 1/18                     (d) 0

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Question 3

Now it was Ravi’s turn. He rolled the dice. What is the probability that he got the sum of the two numbers appearing on the top face of the dice is less than or equal to 12 ?

(a) 1                (b) 5/36              (c) 1/18                  (d) 0

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Question 4

Rahul got next chance. What is the probability that he got the sum of the two numbers appearing on the top face of the dice is equal to 7 ?

(a) 5/9              (b) 5/36               (c) 1/6                      (d) 0

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Question 5
Now it was Ravi’s turn. He rolled the dice. What is the probability that he got the sum of the two numbers appearing on the top face of the dice is greater than 8 ?
(a) 1               (b) 5/36               (c) 1/18                        (d) 5/18

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Transcript

Question Rahul and Ravi planned to play Business ( board game) in which they were supposed to use two diceFirst dice Second dice Question 1 Ravi got first chance to roll the dice. What is the probability that he got the sum of the two numbers appearing on the top face of the dice is 8? (a) 1/26 (b) 5/36 (c) 1/18 (d) 0Probability that sum of two numbers is 8 = (π‘π‘’π‘šπ‘π‘’π‘Ÿ π‘œπ‘“ π‘œπ‘’π‘‘π‘π‘œπ‘šπ‘’π‘  π‘€β„Žπ‘’π‘Ÿπ‘’ π‘ π‘’π‘š 𝑖𝑠 8)/(π‘‡π‘œπ‘‘π‘Žπ‘™ π‘›π‘’π‘šπ‘π‘’π‘Ÿ π‘œπ‘“ π‘œπ‘’π‘‘π‘π‘œπ‘šπ‘’π‘ ) = πŸ“/πŸ‘πŸ” So, correct answer is (b) Question 2 Rahul got next chance. What is the probability that he got the sum of the two numbers appearing on the top face of the dice is 13? (a) 1 (b) 5/36 (c) 1/18 (d) 0Number of outcomes where sum is 13 = 0 Probability that sum of two numbers is 13 = (π‘π‘’π‘šπ‘π‘’π‘Ÿ π‘œπ‘“ π‘œπ‘’π‘‘π‘π‘œπ‘šπ‘’π‘  π‘€β„Žπ‘’π‘Ÿπ‘’ π‘ π‘’π‘š 𝑖𝑠 13)/(π‘‡π‘œπ‘‘π‘Žπ‘™ π‘›π‘’π‘šπ‘π‘’π‘Ÿ π‘œπ‘“ π‘œπ‘’π‘‘π‘π‘œπ‘šπ‘’π‘ ) = 0/36 = 0 So, correct answer is (d) Question 3 Now it was Ravi’s turn. He rolled the dice. What is the probability that he got the sum of the two numbers appearing on the top face of the dice is less than or equal to 12 ? (a) 1 (b) 5/36 (c) 1/18 (d) 0Number of outcomes where sum is less than or equal to 12 = 36 Probability that sum of two numbers is less than or equal to 12 = (π‘π‘’π‘šπ‘π‘’π‘Ÿ π‘œπ‘“ π‘œπ‘’π‘‘π‘π‘œπ‘šπ‘’π‘  π‘€β„Žπ‘’π‘Ÿπ‘’ π‘ π‘’π‘š 𝑖𝑠 𝑙𝑒𝑠𝑠 π‘‘β„Žπ‘Žπ‘› π‘œπ‘Ÿ π‘’π‘žπ‘’π‘Žπ‘™ π‘‘π‘œ 12)/(π‘‡π‘œπ‘‘π‘Žπ‘™ π‘›π‘’π‘šπ‘π‘’π‘Ÿ π‘œπ‘“ π‘œπ‘’π‘‘π‘π‘œπ‘šπ‘’π‘ ) = 36/36 = 1 So, correct answer is (a) Question 4 Rahul got next chance. What is the probability that he got the sum of the two numbers appearing on the top face of the dice is equal to 7 ? (a) 5/9 (b) 5/36 (c) 1/6 (d) 0Number of outcomes where sum is 7 = 6 Probability that sum of two numbers is 7 = (π‘π‘’π‘šπ‘π‘’π‘Ÿ π‘œπ‘“ π‘œπ‘’π‘‘π‘π‘œπ‘šπ‘’π‘  π‘€β„Žπ‘’π‘Ÿπ‘’ π‘ π‘’π‘š 𝑖𝑠 7)/(π‘‡π‘œπ‘‘π‘Žπ‘™ π‘›π‘’π‘šπ‘π‘’π‘Ÿ π‘œπ‘“ π‘œπ‘’π‘‘π‘π‘œπ‘šπ‘’π‘ ) = 6/36 = 𝟏/πŸ” So, correct answer is (c) Question 5 Now it was Ravi’s turn. He rolled the dice. What is the probability that he got the sum of the two numbers appearing on the top face of the dice is greater than 8 ? (a) 1 (b) 5/36 (c) 1/18 (d) 5/18Number of outcomes where sum is greater than 8 = 4 + 3 + 2 + 1 = 10 Probability that sum of two numbers is greater than 8 = (π‘π‘’π‘šπ‘π‘’π‘Ÿ π‘œπ‘“ π‘œπ‘’π‘‘π‘π‘œπ‘šπ‘’π‘  π‘€β„Žπ‘’π‘Ÿπ‘’ π‘ π‘’π‘š 𝑖𝑠 π‘”π‘Ÿπ‘’π‘Žπ‘‘π‘’π‘Ÿ π‘‘β„Žπ‘Žπ‘› 8)/(π‘‡π‘œπ‘‘π‘Žπ‘™ π‘›π‘’π‘šπ‘π‘’π‘Ÿ π‘œπ‘“ π‘œπ‘’π‘‘π‘π‘œπ‘šπ‘’π‘ ) = 10/36 = πŸ“/πŸπŸ– So, correct answer is (d)

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo