Ex 9.3, 11 - Chapter 9 Class 9 Circles

Last updated at July 22, 2026 by

Ex 9.3, 11 - ABC and ADC are two right triangles with - Ex 9.3 - Ex 9.3

part 2 - Ex 9.3, 11 - Ex 9.3 - Serial order wise - Chapter 9 Class 9 Circles

 

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Ex 9.3, 11 ABC and ADC are two right triangles with common hypotenuse AC. Prove that ∠CAD = ∠CBD. Given: ∆ABC with ∠ B = 90° & ∆ADC with ∠ D = 90° To prove: ∠CAD = ∠CBD Proof: Considering quadrilateral ABCD ∠B + ∠D = 90° + 90° ⇒ ∠B + ∠D = 180° So, sum of one pair of opposite angles of quadrilateral ABCD is 180° ∴ ABCD is a cyclic quadrilateral We draw a circle in which ABCD is a cyclic quadrilateral We consider AC as diameter and draw a circle For points C & D, & segment CDABC ∠CAD & ∠CBD are angles in the same segment So, they must be equal ∴ ∠CAD = ∠CBD Hence proved

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