Angle subtended by arc at the centre
Angle subtended by arc at the centre
Last updated at April 16, 2024 by Teachoo
Ex 9.3, 10 If circles are drawn taking two sides of a triangle as diameters, prove that the point of intersection of these circles lie on the third side Given: ABC Side AB as diameter for circle C1 & side AC as diameter for C2 Point of intersection of C1 & C2 is A & D To prove: Point of intersection lies in 3rd side, i.e., D lies on BC. Construction: Let us join AD Proof Now, ADB + ADC = 90 + 90 = 180 Since the sum of angles is 180 , they form a linear pair. Linear pair can only happen on a line. Therefore, BDC is a line. D lies on the line segment BC. Hence proved