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Question 14 - Triangles with same base & same parallel lines - Areas of Parallelograms and Triangles
Last updated at April 16, 2024 by Teachoo
Triangles with same base & same parallel lines
Areas of Parallelograms and Triangles
Concept wise
- Introduction
- Paralleograms with same base & same parallel lines
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Triangles with same base & same parallel lines
- Paralleograms & triangles with same base & same parallel lines
- Median divides triangle into two triangles of equal area
Transcript
Question 14 In figure, AP BQ CR. Prove that ar(AQC) = ar(PBR). Given: AP BQ CR To prove: ar(AQC) = ar(PBR) Proof: Since ABQ and PBQ lie on the same base BQ and are between parallel lines BQ & AP ar(ABQ) = ar(PBQ) Also, CBQ and RBQ lie on the same base BQ and are between parallel lines BQ & CR ar(CBQ) = ar(RBQ) Adding (1) & (2) ar(AQB) + ar(BQC) = ar(PBQ) + ar(QBR) ar(AQC) = ar(PBR). Hence proved
