In the figure, quadrilateral ABCD is circumscribing a circle with centre O and AD⊥AB. If radius of incircle is 10cm, then the value of x is
CBSE Class 10 Sample Paper for 2021 Boards - Maths Standard
Question 1 (Choice - 2)
Question 2
Question 3 Important
Question 4
Question 5 (Choice - 1)
Question 5 (Choice - 2)
Question 6
Question 7 (Choice - 1)
Question 7 (Choice - 2)
Question 8 Important
Question 9 (Choice - 1)
Question 9 (Choice - 2) Important
Question 10
Question 11 Important
Question 12
Question 13
Question 14
Question 15
Question 16 (Choice - 1)
Question 16 (Choice - 2)
Question 17 (Case Based Question) Important
Question 18 (Case Based Question) Important
Question 19 (Case Based Question) Important
Question 20 (Case Based Question) Important
Question 21 Important
Question 22 (Choice - 1)
Question 22 (Choice - 2)
Question 23 Important
Question 24
Question 25 (Choice - 1)
Question 25 (Choice - 2)
Question 26 Important You are here
Question 27
Question 28 (Choice - 1)
Question 28 (Choice - 2)
Question 29 Important
Question 30 (Choice - 1) Important
Question 30 (Choice - 2)
Question 31 Important
Question 32
Question 33 Important
Question 34 (Choice - 1)
Question 34 (Choice - 2)
Question 35 Important
Question 36 Important
CBSE Class 10 Sample Paper for 2021 Boards - Maths Standard
Last updated at Dec. 16, 2024 by Teachoo
Question 26 In the figure, quadrilateral ABCD is circumscribing a circle with centre O and AD⊥ AB. If radius of incircle is 10 cm, then the value of x is Since Tangent is perpendicular to Radius OS ⊥ AD and OP ⊥ AB Thus, ∠ OSA = 90° and ∠ OPA = 90° And, ∠ SOP = 90° Also, AS = AP (Tangents drawn from external point are equal) Thus, In OPAS, All angles are 90° and Adjacent sides are equal ∴ OPAS is a square So, AP = OS = 10 cm Also, Tangent drawn from external point are equal ∴ CQ = CR = 27 cm And, BP = BQ Given CB = 38 cm CQ + BQ = 38 CQ + BP = 38 27 + BP = 38 BP = 38 − 27 BP = 11 cm Thus, x = AB = AP + BP = 10 + 11 = 21 cm