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Question 3 - Paralleograms & triangles with same base & same parallel lines - Areas of Parallelograms and Triangles
Last updated at April 16, 2024 by Teachoo
Paralleograms & triangles with same base & same parallel lines
Areas of Parallelograms and Triangles
Concept wise
- Introduction
- Paralleograms with same base & same parallel lines
- Triangles with same base & same parallel lines
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Paralleograms & triangles with same base & same parallel lines
- Median divides triangle into two triangles of equal area
Transcript
Question 3 P and Q are any two points lying on the sides DC and AD respectively of a parallelogram ABCD. Show that ar (APB) = ar (BQC). Given: A parallelogram ABCD where P & Q are any points on DC and AD resp. To prove: ar (APB) = ar (BQC) Proof: ABCD is a parallelogram So, AB CD & AD BC From (1) & (2) Area ( APB) = Area (BQC) Hence proved
