How to find value of Polynomial at a point? (Video) - Teachoo

Value of Polynomial at a point - Part 2
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Notationp(x) x3 + 2x2 − 5x − 6 p(y) 7y2 − 11y + 4 Notationp(x) Value at a pointValue of Polynomial at a pointFor Polynomial p(x) = x3 + 2x2 − 5x − 6 At x = 1 p(1) = (1)3 + 2(1)2 − 5(1) − 6 = 1 + 2 − 5 − 6 = −8 For Polynomial p(x) = 7x2 − 11x + 4 At x = 1 p(1) = 7(1)2 − 11(1) + 4 = 7 − 11 + 4 = 0 Let’s do an example…For p(x) = 5x3 − 2x2 + 3x − 6, find p(−1), p(2), p(−2)Given p(x) = 5x3 − 2x2 + 3x − 6 For x = −1 p(−1) = 5(−1)3 − 2(−1)2 + 3(−1) − 6 = −5 − 2 − 3 − 6 = −16 So p(−1) = −16

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo