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Ex 8.1, 9 In parallelogram ABCD, two points P and Q are taken on diagonal BD such that DP = BQ Show that: APD CQB Given: ABCD is a parallelogram where DP = BQ To prove: APD CQB Proof: Now, AD BC and transversal BD. ADP = CBQ In APD and CQB, AD = CB ADP = CBQ DP = BQ APD CQB Ex 8.1, 9 In parallelogram ABCD, two points P and Q are taken on diagonal BD such that DP = BQ Show that: (ii) AP = CQ In previous part, we proved that APD CQB, AP = CQ Ex 8.1, 9 In parallelogram ABCD, two points P and Q are taken on diagonal BD such that DP = BQ Show that: (iii) AQB CPD Since, AB DC and transversal BD. ABQ = CDP In AQB and CPD, AB = CD ABQ = CDP BQ = DP AQB CPD Ex 8.1, 9 In parallelogram ABCD, two points P and Q are taken on diagonal BD such that DP = BQ. Show that: (iv) AQ = CP In previous part, we proved that AQB CPD, AQ = CP Ex 8.1, 9 In parallelogram ABCD, two points P and Q are taken on diagonal BD such that DP = BQ. Show that: (v) APCQ is a parallelogram In part (ii) & (iv) we proved that AP = CQ and AQ = CP Since both pairs of opposite sides in APCQ are equal, APCQ is a parallelogram.

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo