Multiple Choice Questions - Chapter 1 Class 9 Maths (with Videos) - Te

Multiple Choice Questions - Chapter 1 Class 9 Maths - Part 2
Multiple Choice Questions - Chapter 1 Class 9 Maths - Part 3

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 √10 × √15 is equal to (A) 6√5 (B) 5√6 (C) √25 (D) 10√5 Now,  √10 × √15=" " √(2 × 5) " × " √(3 × 5) = √2 × √5 " " ×" " √3 × √5 = 𝟓√𝟔  The value of (√32 + √48)/(√8 + √12) is equal to (A) √2 (B) 2 (C) 4 (D) 8 Now, (√32 + √48)/(√8 + √12) = (√(16 × 2) + √(16 × 3))/(√(4 × 2) + √(4 × 3)) = (4√2 + 4√3)/(2√2 + 2√3) = (4(√2 + √3))/(2(√2 + √3))  After rationalising the denominator of 7/(3√3 − 2√2) , we get the denominator as (A) 13 (B) 19 (C) 5 (D) 35 We know 7/((3√3 − 2√2)) = 7/((3√3 − 2√2)) × ((3√3 + 2√2))/((3√3 + 2√2)) = (7(3√3+ 2√2))/((3√3)^2 − (2√2)^2 ) = (7(3√3+ 2√2))/(9 × 3 − 4 × 2)

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo