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Example 8 - Chapter 7 Class 9 Triangles
Last updated at April 16, 2024 by Teachoo
Chapter 7 Class 9 Triangles
Serial order wise
Transcript
Example 8 P is a point equidistant from two lines l and m intersecting at point A (see figure). Show that the line AP bisects the angle between them. Given: PB = PC & PBA = PCA = 90 To prove: PAB = PAC Proof In PAB and PAC. PBA = PCA PA = PA PB = PC So, PAB PAC PAB = PAC Hence proved.
