Question 3 - Side inequality - Chapter 7 Class 9 Triangles

Last updated at Dec. 13, 2024 by

Ex 7.4, 3 - In figure, ∠B < ∠A and ∠C < ∠D. Show that - Ex 7.4

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Ex7.4, 3 In the given figure, ∠B < ∠A and ∠C < ∠D. Show that AD < BC. In ΔAOB, ∠B < ∠A ⇒ AO < BO (Side opposite to the greater angle is longer) In ΔCOD, ∠C < ∠D OD < OC (Side opposite to the greater angle is longer) Adding equations (1) and (2), AO + OD < BO + OC AD < BC Hence proved

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