Ex 7.1, 6 - Chapter 7 Class 9 Triangles

Last updated at Dec. 13, 2024 by

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Ex 7.1, 6 In the given figure, AC = AE, AB = AD and BAD = EAC. Show that BC = DE. Given: AC = AE AB = AD BAD = EAC To prove: BC = DE Proof: Given that BAD = EAC BAD + DAC = EAC + DAC BAC = DAE In ABC and ADE, AB = AD BAC = DAE AC = AE ABC ADE BC = DE Hence proved

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