Ex 6.1,3 - Chapter 6 Class 9 Lines and Angles

Last updated at April 16, 2024 by

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Ex6.1, 3 In the given figure, ∠PQR = ∠PRQ, then prove that ∠PQS = ∠PRT. Let ∠PQR = x Hence, ∠PRQ = x Now, ∠PQS + ∠PQR = 180° ∠PQS = 180° − ∠PQR ∠PQS = 180° − x Also, we can say ∠PRT + ∠PRQ = 180° ∠PRT = 180° − ∠PRQ ∠PRT = 180° − x From (1) & (2) ∠PQS = ∠PRT Hence proved.

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo