Ex 6.1,3 - Chapter 6 Class 9 Lines and Angles

Last updated at August 14, 2026 by

Ex 6.1, 3 - In given figure, ∠PQR = ∠PRQ, then prove - Ex 6.1 - Ex 6.1

part 2 - Ex 6.1,3 - Ex 6.1 - Serial order wise - Chapter 6 Class 9 Lines and Angles

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Transcript

Ex6.1, 3 In the given figure, ∠PQR = ∠PRQ, then prove that ∠PQS = ∠PRT. Let ∠PQR = x Hence, ∠PRQ = x Now, ∠PQS + ∠PQR = 180° ∠PQS = 180° − ∠PQR ∠PQS = 180° − x Also, we can say ∠PRT + ∠PRQ = 180° ∠PRT = 180° − ∠PRQ ∠PRT = 180° − x From (1) & (2) ∠PQS = ∠PRT Hence proved.

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