Question 27 (OR 2nd question) - CBSE Class 10 Sample Paper for 2020 Boards - Maths Standard - Solutions of Sample Papers for Class 10 Boards

Last updated at Dec. 16, 2024 by Teachoo

If HCF of 144 and 180 is expressed in the form 13m − 16. Find the value of m.

Question 27 (OR 2nd question) - CBSE Class 10 Sample Paper for 2020 Boards - Maths Standard - Part 2

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Question 27 (OR 2nd question) If HCF of 144 and 180 is expressed in the form 13m − 16. Find the value of m. To find HCF of 144 and 180, We do prime factorization of both 180 = 2 × 2 × 3 × 3 × 5 144 = 2 × 2 × 2 × 2 × 3 × 3 ∴ HCF = 2 × 2 × 3 × 3 = 36 Writing HCF in terms of 13m − 16 HCF = 13m − 16 36 = 13m − 16 36 + 16 = 13m 52 = 13m 13m = 52 m = 52/13 m = 4

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo

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