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Example 18 (i) - Chapter 2 Class 9 Polynomials
Last updated at April 16, 2024 by Teachoo
Chapter 2 Class 9 Polynomials
Concept wise
- Definition
- Degree & Coefficient of a polynomial
- Value of a polynomial at a given point
- Verifying Zeroes of a polynomial
- Finding Zeroes of a polynomial
- Remainder Theoram
- Check if factor
- Factorisation by middle term
- Factorisation by factor formula
- Factorizing cubic equation
- Identity I - IV
- Identity V
-
Identity VI & VII
- Identity VIII
Transcript
Example 23 Evaluate each of the following using suitable identities: (104)3 We write 104= 100 + 4 (104)3 = (100 + 4)3 Using (a + b)3 = a3 + b3 + 3ab(a + b) Where a = 100 & b = 4 = (100)3 + (4) 3 + 3(100)(4)(100 + 4) = 1000000 + 64 + 3(100)(4)(104) = 1000000 + 64 + 124800 = 1124864
