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Example 14 - Chapter 2 Class 9 Polynomials
Last updated at April 16, 2024 by Teachoo
Chapter 2 Class 9 Polynomials
Concept wise
- Definition
- Degree & Coefficient of a polynomial
- Value of a polynomial at a given point
- Verifying Zeroes of a polynomial
- Finding Zeroes of a polynomial
- Remainder Theoram
- Check if factor
- Factorisation by middle term
- Factorisation by factor formula
- Factorizing cubic equation
- Identity I - IV
-
Identity V
- Identity VI & VII
- Identity VIII
Transcript
Example 14 Write (3a + 4b + 5c)2 in expanded form. (3a + 4b + 5c)2 Using (x + y + z)2 = x2 + y2 + z2 + 2xy + 2yz + 2zx Putting x = 3a, y = 4b, z = 5c = (3a)2 + (4b)2 + (5c)2 + 2(3a)(4b) + 2(4b)(5c) + 2(5c)(3a) = 9a2 + 16b2 + 25c2 + (2 × 3 × 4) (a × b) + (2 × 4 × 5) (b × c) + (2 × 5 × 3) (a × c) = 9a2 + 16b2 + 25c2 + 24ab + 40bc + 30ac
