Vector of magnitude 5 units and in the direction opposite to
2i + 3j β 6kΒ isΒ ____________
CBSE Class 12 Sample Paper for 2020 Boards
CBSE Class 12 Sample Paper for 2020 Boards
Last updated at December 16, 2024 by Teachoo
Transcript
Question 15 (OR 2nd Question) Vector of magnitude 5 units and in the direction opposite to 2π Μ + 3π Μ β 6π Μ is ____________ Let π β = 2π Μ + 3π Μ β 6π Μ Magnitude of π β = β(22+32+(β6)2) |π β | = β(4+9+36) = β49 = 7 Unit vector opposite to direction of π β = β1 Γ 1/|π β | . π β = (β1)/7 (2π Μ + 3π Μ β 6π Μ) Thus, Vector with magnitude 1 opposite to π β = (β1)/7 (2π Μ + 3π Μ β 6π Μ) Vector with magnitude 5 opposite to π β = (β5)/7 (2π Μ + 3π Μ β 6π Μ) = 5/7 (β2π Μ β 3π Μ + 6π Μ) Hence, the required vector is π/π (β2π Μ β 3π Μ + 6π Μ)