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Example 12 - Chapter 2 Class 9 Polynomials
Last updated at April 16, 2024 by Teachoo
Chapter 2 Class 9 Polynomials
Concept wise
- Definition
- Degree & Coefficient of a polynomial
- Value of a polynomial at a given point
- Verifying Zeroes of a polynomial
- Finding Zeroes of a polynomial
- Remainder Theoram
- Check if factor
- Factorisation by middle term
- Factorisation by factor formula
- Factorizing cubic equation
-
Identity I - IV
- Identity V
- Identity VI & VII
- Identity VIII
Transcript
Example 12 Evaluate 105 × 106 without multiplying directly. 105 × 106 = (100 + 5) × (100 + 6) Using Identity (x + a) (x + b) = x2 + (a + b)x + ab, where x = 100 , a = 5, b= 6, = (100)2 + (5 + 6) (100) + (5 × 6) = 10000 + (11)(100) + 30 = 10000 + 1100+ 30 = 11130
