Example 12 - Chapter 2 Class 9 Polynomials
Last updated at April 16, 2024 by Teachoo
Examples
Example 1 (i)
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Chapter 2 Class 9 Polynomials
Serial order wise
- Ex 2.1
- Ex 2.2
- Ex 2.3
- Ex 2.4
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Examples
- Remainder Theorem
Transcript
Example 12 Evaluate 105 × 106 without multiplying directly. 105 × 106 = (100 + 5) × (100 + 6) Using Identity (x + a) (x + b) = x2 + (a + b)x + ab, where x = 100 , a = 5, b= 6, = (100)2 + (5 + 6) (100) + (5 × 6) = 10000 + (11)(100) + 30 = 10000 + 1100+ 30 = 11130
