Question 2 - Chapter 2 Class 9 Polynomials (Important Question)

Last updated at April 16, 2024 by

Example 7 - Divide the polynomial 3x4 - 4x3 - 3x - 1 by x - 1 - Remainder Theoram

Example 7 - Chapter 2 Class 9 Polynomials - Part 2
Example 7 - Chapter 2 Class 9 Polynomials - Part 3

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Question 2 (Long division) Divide the polynomial 3x4 – 4x3 – 3x – 1 by x – 1. By long division Question 2 (Remainder theorem) Divide the polynomial 3x4 – 4x2 – 3x – 1 by x – 1. Dividing 3x4 – 4x2 – 3x – 1 by x – 1. Step 1: Put Divisor = 0 x – 1 = 0 x = 1 Step 2: Let p(x) = 3x4 – 4x2 – 3x – 1 Putting x = 1 p(1) = 3(1)4 - 4(1)2 – 3(1) – 1 = 3(1) – 4(1) – 3 – 1 = 3 – 4 – 3 – 1 = –5 Thus, remainder = p(1) = –5

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo