Identity VI & VII
Last updated at April 16, 2024 by Teachoo
Ex 2.4, 8 Factorise each of the following: (i) 8a3 + b3 + 12a2b + 6ab2 8a3 + b3 + 12a2b + 6ab2 = (2a)3 + (b)3 + 12a2b + 6ab2 = (2a)3 + (b)3 + 6ab (2a + b) = (2a)3 + (b)3 + 3(2a)(b) (2a + b) Using (x + y)3 = x3 + y3 + 3xy(x + y) Putting x = 2a, y = b = (2a + b)3 = (2a + b) (2a + b) (2a + b)