Class 9
Chapter 8 Class 9 - Motion

Question 1 - Graph Question (Easy) - Teachoo Questions - Chapter 8 Class 9 - Motion

Last updated at Dec. 16, 2024 by

Find Displacement and Acceleration in region OA and OB. Also tell the type of motion in both the regions. And find the total displacement

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Marking point C in the graph

 

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Motion in region OA = Uniformly accelerated

Motion in region OB = Uniformly retarded

 Total Displacement = Area of ∆ABO

 = Area of ∆OAC + Area of ∆ABC

 = 4m + 4m

 = 8m  

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Transcript

Region OA Acceleration = Slope of OA = (𝑦_2 − 𝑦_1)/(𝑥_2 − 𝑥_1 ) = (4 − 0)/(2 − 0) = 4/2 = 2 m/s2 Displacement = Area under v – t graph = Area of ∆OAC = 1/2 × b × h = 1/2 × 2 × 4 = 4 m Region AB Acceleration = Slope of BA = (𝑦_2 − 𝑦_1)/(𝑥_2 − 𝑥_1 ) = (0 − 4)/(0 − 2) = (−4)/2 = −2 m/s2 Displacement = Area under v – t graph = Area of ∆ABC = 1/2 × b × h = 1/2 × 2 × 4 = 4 km

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CA Maninder Singh is a Chartered Accountant for the past 14 years and a teacher from the past 18 years. He teaches Science, Economics, Accounting and English at Teachoo